Solve 28a^2=6a^2

$$28 a ^ { 2 } = 6 a ^ { 2 }$$

Solve for a

$$a=0$$

Steps by Finding Square Root

Subtract 6a^{2} from both sides.

$$28a^{2}-6a^{2}=0$$

Combine 28a^{2} and -6a^{2} to get 22a^{2}.

$$22a^{2}=0$$

Divide both sides by 22. Zero divided by any non-zero number gives zero.

$$a^{2}=0$$

Take the square root of both sides of the equation.

$$a=0 a=0$$

The equation is now solved. Solutions are the same.

$$a=0$$

Steps Using the Quadratic Formula

Subtract 6a^{2} from both sides.

$$28a^{2}-6a^{2}=0$$

Combine 28a^{2} and -6a^{2} to get 22a^{2}.

$$22a^{2}=0$$

Divide both sides by 22. Zero divided by any non-zero number gives zero.

$$a^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$a=\frac{0±0}{2}$$

Divide 0 by 2.

$$a=0$$