Solve for A_30
A_{30}=\frac{3k+1}{28}
Solve for k
k=\frac{28A_{30}-1}{3}
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28A_{30}=3k+1
The equation is in standard form.
\frac{28A_{30}}{28}=\frac{3k+1}{28}
Divide both sides by 28.
A_{30}=\frac{3k+1}{28}
Dividing by 28 undoes the multiplication by 28.
3k+1=28A_{30}
Swap sides so that all variable terms are on the left hand side.
3k=28A_{30}-1
Subtract 1 from both sides.
\frac{3k}{3}=\frac{28A_{30}-1}{3}
Divide both sides by 3.
k=\frac{28A_{30}-1}{3}
Dividing by 3 undoes the multiplication by 3.
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