Solve 27+(15/60)+(48/3600)

$$27+( \frac{ 15 }{ 60 } )+( \frac{ 48 }{ 3600 } )$$

Evaluate

$$\frac{8179}{300}\approx 27.263333333$$

Solution Steps

Reduce the fraction \frac{15}{60} to lowest terms by extracting and canceling out 15.

$$27+\frac{1}{4}+\frac{48}{3600}$$

Convert 27 to fraction \frac{108}{4}.

$$\frac{108}{4}+\frac{1}{4}+\frac{48}{3600}$$

Since \frac{108}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{108+1}{4}+\frac{48}{3600}$$

Add 108 and 1 to get 109.

$$\frac{109}{4}+\frac{48}{3600}$$

Reduce the fraction \frac{48}{3600} to lowest terms by extracting and canceling out 48.

$$\frac{109}{4}+\frac{1}{75}$$

Least common multiple of 4 and 75 is 300. Convert \frac{109}{4} and \frac{1}{75} to fractions with denominator 300.

$$\frac{8175}{300}+\frac{4}{300}$$

Since \frac{8175}{300} and \frac{4}{300} have the same denominator, add them by adding their numerators.

$$\frac{8175+4}{300}$$

Add 8175 and 4 to get 8179.

$$\frac{8179}{300}$$

Factor

$$\frac{8179}{2 ^ {2} \cdot 3 \cdot 5 ^ {2}} = 27\frac{79}{300} = 27.263333333333332$$