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y^{5}\left(27-x^{3}\right)
Factor out y^{5}.
\left(x-3\right)\left(-x^{2}-3x-9\right)
Consider 27-x^{3}. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 27 and q divides the leading coefficient -1. One such root is 3. Factor the polynomial by dividing it by x-3.
y^{5}\left(x-3\right)\left(-x^{2}-3x-9\right)
Rewrite the complete factored expression. Polynomial -x^{2}-3x-9 is not factored since it does not have any rational roots.