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\left(3x^{2}-4y^{3}\right)\left(9x^{4}+12x^{2}y^{3}+16y^{6}\right)
Rewrite 27x^{6}-64y^{9} as \left(3x^{2}\right)^{3}-\left(4y^{3}\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).