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\frac{729x^{3}+y^{3}+243x^{2}y+27xy^{2}}{27}
Factor out \frac{1}{27}.
\left(9x+y\right)^{3}
Consider 729x^{3}+y^{3}+243x^{2}y+27xy^{2}. Use the binomial cube formula, a^{3}+3a^{2}b+3ab^{2}+b^{3}=\left(a+b\right)^{3}, where a=9x and b=y.
\frac{\left(9x+y\right)^{3}}{27}
Rewrite the complete factored expression.