Factor
\left(3x^{4}-2\right)\left(9x^{8}+6x^{4}+4\right)
Evaluate
27x^{12}-8
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\left(3x^{4}-2\right)\left(9x^{8}+6x^{4}+4\right)
Rewrite 27x^{12}-8 as \left(3x^{4}\right)^{3}-2^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). The following polynomials are not factored since they do not have any rational roots: 3x^{4}-2,9x^{8}+6x^{4}+4.
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