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\left(3u-5v\right)\left(9u^{2}+15uv+25v^{2}\right)
Rewrite 27u^{3}-125v^{3} as \left(3u\right)^{3}-\left(5v\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).