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\left(3u+2v\right)\left(9u^{2}-6uv+4v^{2}\right)
Rewrite 27u^{3}+8v^{3} as \left(3u\right)^{3}+\left(2v\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).