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\left(3m+2n\right)\left(9m^{2}-6mn+4n^{2}\right)
Rewrite 27m^{3}+8n^{3} as \left(3m\right)^{3}+\left(2n\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).