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\left(-2x+3h\right)\left(4x^{2}+6hx+9h^{2}\right)
Rewrite 27h^{3}-8x^{3} as \left(-2x\right)^{3}+\left(3h\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).