Factor
\left(3c+1\right)\left(9c^{2}-3c+1\right)
Evaluate
27c^{3}+1
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\left(3c+1\right)\left(9c^{2}-3c+1\right)
Rewrite 27c^{3}+1 as \left(3c\right)^{3}+1^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right). Polynomial 9c^{2}-3c+1 is not factored since it does not have any rational roots.
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