Factor
\left(3a+1\right)\left(9a^{2}-3a+1\right)
Evaluate
27a^{3}+1
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\left(3a+1\right)\left(9a^{2}-3a+1\right)
Rewrite 27a^{3}+1 as \left(3a\right)^{3}+1^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right). Polynomial 9a^{2}-3a+1 is not factored since it does not have any rational roots.
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