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3\left(9a^{2}b^{2}-6ab+1\right)
Factor out 3.
\left(3ab-1\right)^{2}
Consider 9a^{2}b^{2}-6ab+1. Use the perfect square formula, p^{2}-2pq+q^{2}=\left(p-q\right)^{2}, where p=3ab and q=1.
3\left(3ab-1\right)^{2}
Rewrite the complete factored expression.