Factor
y\left(3y-1\right)\left(9y^{2}+3y+1\right)
Evaluate
y\left(27y^{3}-1\right)
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y\left(27y^{3}-1\right)
Factor out y.
\left(3y-1\right)\left(9y^{2}+3y+1\right)
Consider 27y^{3}-1. Rewrite 27y^{3}-1 as \left(3y\right)^{3}-1^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
y\left(3y-1\right)\left(9y^{2}+3y+1\right)
Rewrite the complete factored expression. Polynomial 9y^{2}+3y+1 is not factored since it does not have any rational roots.
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