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\left(3y-z\right)\left(9y^{2}+3yz+z^{2}\right)
Rewrite 27y^{3}-z^{3} as \left(3y\right)^{3}-z^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).