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\left(3x^{2}-4\right)\left(9x^{4}+12x^{2}+16\right)
Rewrite 27x^{6}-64 as \left(3x^{2}\right)^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). The following polynomials are not factored since they do not have any rational roots: 3x^{2}-4,9x^{4}+12x^{2}+16.