Solve 27*21+21/(21)^2+21=462

$$27 \times 21 + 21 / ( 21 ) ^ { 2 } + 21 = 462$$

Verify

Solution Steps

Rewrite 21^{2} as 21\times 21. Cancel out 21 in both numerator and denominator.

$$27\times 21+\frac{1}{21}+21=462$$

Multiply 27 and 21 to get 567.

$$567+\frac{1}{21}+21=462$$

Convert 567 to fraction \frac{11907}{21}.

$$\frac{11907}{21}+\frac{1}{21}+21=462$$

Since \frac{11907}{21} and \frac{1}{21} have the same denominator, add them by adding their numerators.

$$\frac{11907+1}{21}+21=462$$

Add 11907 and 1 to get 11908.

$$\frac{11908}{21}+21=462$$

Convert 21 to fraction \frac{441}{21}.

$$\frac{11908}{21}+\frac{441}{21}=462$$

Since \frac{11908}{21} and \frac{441}{21} have the same denominator, add them by adding their numerators.

$$\frac{11908+441}{21}=462$$

Add 11908 and 441 to get 12349.

$$\frac{12349}{21}=462$$

Convert 462 to fraction \frac{9702}{21}.

$$\frac{12349}{21}=\frac{9702}{21}$$

Compare \frac{12349}{21} and \frac{9702}{21}.

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