Solve 27^frac{1{3}}(7/63)*lg10=

$$27 ^ { \frac { 1 } { 3 } } ( \frac { 7 } { 63 } ) \cdot \lg 10 =$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

Calculate 27 to the power of \frac{1}{3} and get 3.

$$3\times \frac{7}{63}\log(10)$$

Reduce the fraction \frac{7}{63} to lowest terms by extracting and canceling out 7.

$$3\times \frac{1}{9}\log(10)$$

Multiply 3 and \frac{1}{9} to get \frac{1}{3}.

$$\frac{1}{3}\log(10)$$

The common logarithm of 10 is 1.

$$\frac{1}{3}\times 1$$

Multiply \frac{1}{3} and 1 to get \frac{1}{3}.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$