Solve 27/4*(2*3)<=(5*2+3)*(7-6+21)

$$27 / 4 * ( 2 \times 3 ) < = ( 5 \times 2 + 3 ) \times ( 7 - 6 + 21 )$$

Verify

Solution Steps

Express \frac{27}{4}\times 2 as a single fraction.

$$\frac{27\times 2}{4}\times 3<\left(5\times 2+3\right)\left(7-6+21\right)$$

Multiply 27 and 2 to get 54.

$$\frac{54}{4}\times 3<\left(5\times 2+3\right)\left(7-6+21\right)$$

Reduce the fraction \frac{54}{4} to lowest terms by extracting and canceling out 2.

$$\frac{27}{2}\times 3<\left(5\times 2+3\right)\left(7-6+21\right)$$

Express \frac{27}{2}\times 3 as a single fraction.

$$\frac{27\times 3}{2}<\left(5\times 2+3\right)\left(7-6+21\right)$$

Multiply 27 and 3 to get 81.

$$\frac{81}{2}<\left(5\times 2+3\right)\left(7-6+21\right)$$

Multiply 5 and 2 to get 10.

$$\frac{81}{2}<\left(10+3\right)\left(7-6+21\right)$$

Add 10 and 3 to get 13.

$$\frac{81}{2}<13\left(7-6+21\right)$$

Subtract 6 from 7 to get 1.

$$\frac{81}{2}<13\left(1+21\right)$$

Add 1 and 21 to get 22.

$$\frac{81}{2}<13\times 22$$

Multiply 13 and 22 to get 286.

$$\frac{81}{2}<286$$

Convert 286 to fraction \frac{572}{2}.

$$\frac{81}{2}<\frac{572}{2}$$

Compare \frac{81}{2} and \frac{572}{2}.

$$\text{true}$$