Solve 26x^4-3x^9/6y^-0

$$26 x ^ { 4 } - 3 \frac { x ^ { 9 } } { 6 } y ^ { - 0 }$$

Evaluate

$$-\frac{x^{9}}{2}+26x^{4}$$

Short Solution Steps

Calculate y to the power of 0 and get 1.

$$26x^{4}-3\times \frac{x^{9}}{6}\times 1$$

Multiply 3 and 1 to get 3.

$$26x^{4}-3\times \frac{x^{9}}{6}$$

Cancel out 6, the greatest common factor in 3 and 6.

$$26x^{4}-\frac{x^{9}}{2}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 26x^{4} times \frac{2}{2}.

$$\frac{2\times 26x^{4}}{2}-\frac{x^{9}}{2}$$

Since \frac{2\times 26x^{4}}{2} and \frac{x^{9}}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2\times 26x^{4}-x^{9}}{2}$$

Do the multiplications in 2\times 26x^{4}-x^{9}.

$$\frac{52x^{4}-x^{9}}{2}$$

Factor

$$\frac{x^{4}\left(52-x^{5}\right)}{2}$$

Solution Steps

Factor out \frac{1}{2}.

$$\frac{52x^{4}-x^{9}y^{0}}{2}$$

Consider 52x^{4}-x^{9}. Factor out x^{4}.

$$x^{4}\left(52-x^{5}\right)$$

Rewrite the complete factored expression. Polynomial 52-x^{5} is not factored since it does not have any rational roots.

$$\frac{x^{4}\left(52-x^{5}\right)}{2}$$