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26x^{2}-156x+205=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-156\right)±\sqrt{\left(-156\right)^{2}-4\times 26\times 205}}{2\times 26}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 26 for a, -156 for b, and 205 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-156\right)±\sqrt{24336-4\times 26\times 205}}{2\times 26}
Square -156.
x=\frac{-\left(-156\right)±\sqrt{24336-104\times 205}}{2\times 26}
Multiply -4 times 26.
x=\frac{-\left(-156\right)±\sqrt{24336-21320}}{2\times 26}
Multiply -104 times 205.
x=\frac{-\left(-156\right)±\sqrt{3016}}{2\times 26}
Add 24336 to -21320.
x=\frac{-\left(-156\right)±2\sqrt{754}}{2\times 26}
Take the square root of 3016.
x=\frac{156±2\sqrt{754}}{2\times 26}
The opposite of -156 is 156.
x=\frac{156±2\sqrt{754}}{52}
Multiply 2 times 26.
x=\frac{2\sqrt{754}+156}{52}
Now solve the equation x=\frac{156±2\sqrt{754}}{52} when ± is plus. Add 156 to 2\sqrt{754}.
x=\frac{\sqrt{754}}{26}+3
Divide 156+2\sqrt{754} by 52.
x=\frac{156-2\sqrt{754}}{52}
Now solve the equation x=\frac{156±2\sqrt{754}}{52} when ± is minus. Subtract 2\sqrt{754} from 156.
x=-\frac{\sqrt{754}}{26}+3
Divide 156-2\sqrt{754} by 52.
x=\frac{\sqrt{754}}{26}+3 x=-\frac{\sqrt{754}}{26}+3
The equation is now solved.
26x^{2}-156x+205=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
26x^{2}-156x+205-205=-205
Subtract 205 from both sides of the equation.
26x^{2}-156x=-205
Subtracting 205 from itself leaves 0.
\frac{26x^{2}-156x}{26}=-\frac{205}{26}
Divide both sides by 26.
x^{2}+\left(-\frac{156}{26}\right)x=-\frac{205}{26}
Dividing by 26 undoes the multiplication by 26.
x^{2}-6x=-\frac{205}{26}
Divide -156 by 26.
x^{2}-6x+\left(-3\right)^{2}=-\frac{205}{26}+\left(-3\right)^{2}
Divide -6, the coefficient of the x term, by 2 to get -3. Then add the square of -3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-6x+9=-\frac{205}{26}+9
Square -3.
x^{2}-6x+9=\frac{29}{26}
Add -\frac{205}{26} to 9.
\left(x-3\right)^{2}=\frac{29}{26}
Factor x^{2}-6x+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-3\right)^{2}}=\sqrt{\frac{29}{26}}
Take the square root of both sides of the equation.
x-3=\frac{\sqrt{754}}{26} x-3=-\frac{\sqrt{754}}{26}
Simplify.
x=\frac{\sqrt{754}}{26}+3 x=-\frac{\sqrt{754}}{26}+3
Add 3 to both sides of the equation.