Solve 262x^3y/3a^2:4xy^2/9a=

$$26 \frac { 2 x ^ { 3 } y } { 3 a ^ { 2 } } : \frac { 4 x y ^ { 2 } } { 9 a } =$$

Evaluate

$$\frac{39x^{2}}{ay}$$

Solution Steps

Express 26\times \frac{2x^{3}y}{3a^{2}} as a single fraction.

$$\frac{\frac{26\times 2x^{3}y}{3a^{2}}}{\frac{4xy^{2}}{9a}}$$

Divide \frac{26\times 2x^{3}y}{3a^{2}} by \frac{4xy^{2}}{9a} by multiplying \frac{26\times 2x^{3}y}{3a^{2}} by the reciprocal of \frac{4xy^{2}}{9a}.

$$\frac{26\times 2x^{3}y\times 9a}{3a^{2}\times 4xy^{2}}$$

Cancel out 2\times 2\times 3axy in both numerator and denominator.

$$\frac{3\times 13x^{2}}{ay}$$

Multiply 3 and 13 to get 39.

$$\frac{39x^{2}}{ay}$$

Differentiate w.r.t. x

$$\frac{78x}{ay}$$