Solve for f (complex solution)
f=\frac{\sqrt{-1+\frac{5}{x}}}{26x}
x\neq 0
Solve for f
f=\frac{\sqrt{5-x}}{26x^{\frac{3}{2}}}
x>0\text{ and }x\leq 5
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26xf=\sqrt{\frac{5-x}{x}}
The equation is in standard form.
\frac{26xf}{26x}=\frac{\sqrt{-1+\frac{5}{x}}}{26x}
Divide both sides by 26x.
f=\frac{\sqrt{-1+\frac{5}{x}}}{26x}
Dividing by 26x undoes the multiplication by 26x.
26xf=\sqrt{\frac{5-x}{x}}
The equation is in standard form.
\frac{26xf}{26x}=\frac{\sqrt{5-x}}{\sqrt{x}\times 26x}
Divide both sides by 26x.
f=\frac{\sqrt{5-x}}{\sqrt{x}\times 26x}
Dividing by 26x undoes the multiplication by 26x.
f=\frac{\sqrt{5-x}}{26x^{\frac{3}{2}}}
Divide \frac{\sqrt{5-x}}{\sqrt{x}} by 26x.
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