Solve 26<14-4x|+10

$$26 < 14 - 4 x | + 10$$

Solve for x

$$x<-\frac{3}{10}$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 10 is 10.

$$26<14-4x\times 10$$

Multiply 4 and 10 to get 40.

$$26<14-40x$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$14-40x>26$$

Subtract 14 from both sides.

$$-40x>26-14$$

Subtract 14 from 26 to get 12.

$$-40x>12$$

Divide both sides by -40. Since -40 is negative, the inequality direction is changed.

$$x<\frac{12}{-40}$$

Reduce the fraction \frac{12}{-40} to lowest terms by extracting and canceling out 4.

$$x<-\frac{3}{10}$$