Solve 256x^2+199x+256=0

$$256 x ^ { 2 } + 199 x + 256 = 0$$

Solve for x (complex solution)

$$x=\frac{-199+3\sqrt{24727}i}{512}\approx -0.388671875+0.921376239i$$

$$x=\frac{-3\sqrt{24727}i-199}{512}\approx -0.388671875-0.921376239i$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$256x^{2}+199x+256=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 256 for a, 199 for b, and 256 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-199±\sqrt{199^{2}-4\times 256\times 256}}{2\times 256}$$

Square 199.

$$x=\frac{-199±\sqrt{39601-4\times 256\times 256}}{2\times 256}$$

Multiply -4 times 256.

$$x=\frac{-199±\sqrt{39601-1024\times 256}}{2\times 256}$$

Multiply -1024 times 256.

$$x=\frac{-199±\sqrt{39601-262144}}{2\times 256}$$

Add 39601 to -262144.

$$x=\frac{-199±\sqrt{-222543}}{2\times 256}$$

Take the square root of -222543.

$$x=\frac{-199±3\sqrt{24727}i}{2\times 256}$$

Multiply 2 times 256.

$$x=\frac{-199±3\sqrt{24727}i}{512}$$

Now solve the equation x=\frac{-199±3\sqrt{24727}i}{512} when ± is plus. Add -199 to 3i\sqrt{24727}.

$$x=\frac{-199+3\sqrt{24727}i}{512}$$

Now solve the equation x=\frac{-199±3\sqrt{24727}i}{512} when ± is minus. Subtract 3i\sqrt{24727} from -199.

$$x=\frac{-3\sqrt{24727}i-199}{512}$$

The equation is now solved.

$$x=\frac{-199+3\sqrt{24727}i}{512} x=\frac{-3\sqrt{24727}i-199}{512}$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$256x^{2}+199x+256=0$$

Subtract 256 from both sides of the equation.

$$256x^{2}+199x+256-256=-256$$

Subtracting 256 from itself leaves 0.

$$256x^{2}+199x=-256$$

Divide both sides by 256.

$$\frac{256x^{2}+199x}{256}=-\frac{256}{256}$$

Dividing by 256 undoes the multiplication by 256.

$$x^{2}+\frac{199}{256}x=-\frac{256}{256}$$

Divide -256 by 256.

$$x^{2}+\frac{199}{256}x=-1$$

Divide \frac{199}{256}, the coefficient of the x term, by 2 to get \frac{199}{512}. Then add the square of \frac{199}{512} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+\frac{199}{256}x+\left(\frac{199}{512}\right)^{2}=-1+\left(\frac{199}{512}\right)^{2}$$

Square \frac{199}{512} by squaring both the numerator and the denominator of the fraction.

$$x^{2}+\frac{199}{256}x+\frac{39601}{262144}=-1+\frac{39601}{262144}$$

Add -1 to \frac{39601}{262144}.

$$x^{2}+\frac{199}{256}x+\frac{39601}{262144}=-\frac{222543}{262144}$$

Factor x^{2}+\frac{199}{256}x+\frac{39601}{262144}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{199}{512}\right)^{2}=-\frac{222543}{262144}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+\frac{199}{512}\right)^{2}}=\sqrt{-\frac{222543}{262144}}$$

Simplify.

$$x+\frac{199}{512}=\frac{3\sqrt{24727}i}{512} x+\frac{199}{512}=-\frac{3\sqrt{24727}i}{512}$$

Subtract \frac{199}{512} from both sides of the equation.

$$x=\frac{-199+3\sqrt{24727}i}{512} x=\frac{-3\sqrt{24727}i-199}{512}$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 256

$$x ^ 2 +\frac{199}{256}x +1 = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = -\frac{199}{256} rs = 1$$

Two numbers r and s sum up to -\frac{199}{256} exactly when the average of the two numbers is \frac{1}{2}*-\frac{199}{256} = -\frac{199}{512}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = -\frac{199}{512} - u s = -\frac{199}{512} + u$$

To solve for unknown quantity u, substitute these in the product equation rs = 1

$$(-\frac{199}{512} - u) (-\frac{199}{512} + u) = 1$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$\frac{39601}{262144} - u^2 = 1$$

Simplify the expression by subtracting \frac{39601}{262144} on both sides

$$-u^2 = 1-\frac{39601}{262144} = -\frac{222543}{262144}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = \frac{222543}{262144} u = \pm\sqrt{\frac{222543}{262144}} = \pm \frac{\sqrt{222543}}{512}$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =-\frac{199}{512} - \frac{\sqrt{222543}}{512} = -0.389 - 0.921i s = -\frac{199}{512} + \frac{\sqrt{222543}}{512} = -0.389 + 0.921i$$