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\frac{\left(252\times 2+1\right)\times 5}{2\left(20\times 5+1\right)}
Divide \frac{252\times 2+1}{2} by \frac{20\times 5+1}{5} by multiplying \frac{252\times 2+1}{2} by the reciprocal of \frac{20\times 5+1}{5}.
\frac{\left(504+1\right)\times 5}{2\left(20\times 5+1\right)}
Multiply 252 and 2 to get 504.
\frac{505\times 5}{2\left(20\times 5+1\right)}
Add 504 and 1 to get 505.
\frac{2525}{2\left(20\times 5+1\right)}
Multiply 505 and 5 to get 2525.
\frac{2525}{2\left(100+1\right)}
Multiply 20 and 5 to get 100.
\frac{2525}{2\times 101}
Add 100 and 1 to get 101.
\frac{2525}{202}
Multiply 2 and 101 to get 202.
\frac{25}{2}
Reduce the fraction \frac{2525}{202} to lowest terms by extracting and canceling out 101.