Solve 250000*0.9left(1+yright)0.915*1.12*1.03=210000

$$250000 \times 0.9 \left( 1+y \right) 0.915 \cdot 1.12 \cdot 1.03=210000$$

Solve for y

$$y=-\frac{6547}{56547}\approx -0.115779794$$

Steps for Solving Linear Equation

Multiply 250000 and 0.9 to get 225000.

$$225000\left(1+y\right)\times 0.915\times 1.12\times 1.03=210000$$

Multiply 225000 and 0.915 to get 205875.

$$205875\left(1+y\right)\times 1.12\times 1.03=210000$$

Multiply 205875 and 1.12 to get 230580.

$$230580\left(1+y\right)\times 1.03=210000$$

Multiply 230580 and 1.03 to get 237497.4.

$$237497.4\left(1+y\right)=210000$$

Use the distributive property to multiply 237497.4 by 1+y.

$$237497.4+237497.4y=210000$$

Subtract 237497.4 from both sides.

$$237497.4y=210000-237497.4$$

Subtract 237497.4 from 210000 to get -27497.4.

$$237497.4y=-27497.4$$

Divide both sides by 237497.4.

$$y=\frac{-27497.4}{237497.4}$$

Expand \frac{-27497.4}{237497.4} by multiplying both numerator and the denominator by 10.

$$y=\frac{-274974}{2374974}$$

Reduce the fraction \frac{-274974}{2374974} to lowest terms by extracting and canceling out 42.

$$y=-\frac{6547}{56547}$$