Solve 2500(1+x)^2=3025

$$2500 ( 1 + x ) ^ { 2 } = 3025$$

Solve for x

$$x=\frac{1}{10}=0.1$$

$$x = -\frac{21}{10} = -2\frac{1}{10} = -2.1$$

Steps by Finding Square Root

Divide both sides by 2500.

$$\frac{2500\left(x+1\right)^{2}}{2500}=\frac{3025}{2500}$$

Dividing by 2500 undoes the multiplication by 2500.

$$\left(x+1\right)^{2}=\frac{3025}{2500}$$

Reduce the fraction \frac{3025}{2500} to lowest terms by extracting and canceling out 25.

$$\left(x+1\right)^{2}=\frac{121}{100}$$

Take the square root of both sides of the equation.

$$x+1=\frac{11}{10} x+1=-\frac{11}{10}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{11}{10}-1 x+1-1=-\frac{11}{10}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{11}{10}-1 x=-\frac{11}{10}-1$$

Subtract 1 from \frac{11}{10}.

$$x=\frac{1}{10}$$

Subtract 1 from -\frac{11}{10}.

$$x=-\frac{21}{10}$$

The equation is now solved.

$$x=\frac{1}{10} x=-\frac{21}{10}$$