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2\left(125a^{3}-27b^{9}\right)
Factor out 2.
\left(5a-3b^{3}\right)\left(25a^{2}+15ab^{3}+9b^{6}\right)
Consider 125a^{3}-27b^{9}. Rewrite 125a^{3}-27b^{9} as \left(5a\right)^{3}-\left(3b^{3}\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
2\left(5a-3b^{3}\right)\left(25a^{2}+15ab^{3}+9b^{6}\right)
Rewrite the complete factored expression.