25(x+40 \% )=11
Solve for x
x=\frac{1}{25}=0.04
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x+\frac{40}{100}=\frac{11}{25}
Divide both sides by 25.
x+\frac{2}{5}=\frac{11}{25}
Reduce the fraction \frac{40}{100} to lowest terms by extracting and canceling out 20.
x=\frac{11}{25}-\frac{2}{5}
Subtract \frac{2}{5} from both sides.
x=\frac{11}{25}-\frac{10}{25}
Least common multiple of 25 and 5 is 25. Convert \frac{11}{25} and \frac{2}{5} to fractions with denominator 25.
x=\frac{11-10}{25}
Since \frac{11}{25} and \frac{10}{25} have the same denominator, subtract them by subtracting their numerators.
x=\frac{1}{25}
Subtract 10 from 11 to get 1.
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