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\frac{25}{3}=x^{2}
Divide both sides by 3.
x^{2}=\frac{25}{3}
Swap sides so that all variable terms are on the left hand side.
x=\frac{5\sqrt{3}}{3} x=-\frac{5\sqrt{3}}{3}
Take the square root of both sides of the equation.
\frac{25}{3}=x^{2}
Divide both sides by 3.
x^{2}=\frac{25}{3}
Swap sides so that all variable terms are on the left hand side.
x^{2}-\frac{25}{3}=0
Subtract \frac{25}{3} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{25}{3}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{25}{3} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{25}{3}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{100}{3}}}{2}
Multiply -4 times -\frac{25}{3}.
x=\frac{0±\frac{10\sqrt{3}}{3}}{2}
Take the square root of \frac{100}{3}.
x=\frac{5\sqrt{3}}{3}
Now solve the equation x=\frac{0±\frac{10\sqrt{3}}{3}}{2} when ± is plus.
x=-\frac{5\sqrt{3}}{3}
Now solve the equation x=\frac{0±\frac{10\sqrt{3}}{3}}{2} when ± is minus.
x=\frac{5\sqrt{3}}{3} x=-\frac{5\sqrt{3}}{3}
The equation is now solved.