Solve 25+1.2x-4.9x^2=0.6x-4.9x^2

$$25+1.2x-4.9 { x }^{ 2 } = 0.6x-4.9 { x }^{ 2 }$$

Solve for x

$$x = -\frac{125}{3} = -41\frac{2}{3} \approx -41.666666667$$

Steps for Solving Linear Equation

Subtract 0.6x from both sides.

$$25+1.2x-4.9x^{2}-0.6x=-4.9x^{2}$$

Combine 1.2x and -0.6x to get 0.6x.

$$25+0.6x-4.9x^{2}=-4.9x^{2}$$

Add 4.9x^{2} to both sides.

$$25+0.6x-4.9x^{2}+4.9x^{2}=0$$

Combine -4.9x^{2} and 4.9x^{2} to get 0.

$$25+0.6x=0$$

Subtract 25 from both sides. Anything subtracted from zero gives its negation.

$$0.6x=-25$$

Divide both sides by 0.6.

$$x=\frac{-25}{0.6}$$

Expand \frac{-25}{0.6} by multiplying both numerator and the denominator by 10.

$$x=\frac{-250}{6}$$

Reduce the fraction \frac{-250}{6} to lowest terms by extracting and canceling out 2.

$$x=-\frac{125}{3}$$