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\left(8+5yz-x\right)\left(8+5yz+x\right)
Rewrite 25y^{2}z^{2}+80yz+64-x^{2} as \left(8+5yz\right)^{2}-x^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(-x+5yz+8\right)\left(x+5yz+8\right)
Reorder the terms.