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\left(5x^{2}-9y^{3}\right)\left(5x^{2}+9y^{3}\right)
Rewrite 25x^{4}-81y^{6} as \left(5x^{2}\right)^{2}-\left(9y^{3}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).