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5\left(5x^{4}-6x^{3}+x^{2}\right)
Factor out 5.
x^{2}\left(5x^{2}-6x+1\right)
Consider 5x^{4}-6x^{3}+x^{2}. Factor out x^{2}.
a+b=-6 ab=5\times 1=5
Consider 5x^{2}-6x+1. Factor the expression by grouping. First, the expression needs to be rewritten as 5x^{2}+ax+bx+1. To find a and b, set up a system to be solved.
a=-5 b=-1
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. The only such pair is the system solution.
\left(5x^{2}-5x\right)+\left(-x+1\right)
Rewrite 5x^{2}-6x+1 as \left(5x^{2}-5x\right)+\left(-x+1\right).
5x\left(x-1\right)-\left(x-1\right)
Factor out 5x in the first and -1 in the second group.
\left(x-1\right)\left(5x-1\right)
Factor out common term x-1 by using distributive property.
5x^{2}\left(x-1\right)\left(5x-1\right)
Rewrite the complete factored expression.