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25x^{4}-729
Calculate 3 to the power of 6 and get 729.
\left(5x^{2}-27\right)\left(5x^{2}+27\right)
Rewrite 25x^{4}-729 as \left(5x^{2}\right)^{2}-27^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right). The following polynomials are not factored since they do not have any rational roots: 5x^{2}-27,5x^{2}+27.