Solve for x
x\in \left(-\infty,-\frac{4}{5}\right)\cup \left(\frac{4}{5},\infty\right)
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x^{2}>\frac{16}{25}
Divide both sides by 25. Since 25 is positive, the inequality direction remains the same.
x^{2}>\left(\frac{4}{5}\right)^{2}
Calculate the square root of \frac{16}{25} and get \frac{4}{5}. Rewrite \frac{16}{25} as \left(\frac{4}{5}\right)^{2}.
|x|>\frac{4}{5}
Inequality holds for |x|>\frac{4}{5}.
x<-\frac{4}{5}\text{; }x>\frac{4}{5}
Rewrite |x|>\frac{4}{5} as x<-\frac{4}{5}\text{; }x>\frac{4}{5}.
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