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x\left(25x+100\right)=0
Factor out x.
x=0 x=-4
To find equation solutions, solve x=0 and 25x+100=0.
25x^{2}+100x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-100±\sqrt{100^{2}}}{2\times 25}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 25 for a, 100 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-100±100}{2\times 25}
Take the square root of 100^{2}.
x=\frac{-100±100}{50}
Multiply 2 times 25.
x=\frac{0}{50}
Now solve the equation x=\frac{-100±100}{50} when ± is plus. Add -100 to 100.
x=0
Divide 0 by 50.
x=-\frac{200}{50}
Now solve the equation x=\frac{-100±100}{50} when ± is minus. Subtract 100 from -100.
x=-4
Divide -200 by 50.
x=0 x=-4
The equation is now solved.
25x^{2}+100x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{25x^{2}+100x}{25}=\frac{0}{25}
Divide both sides by 25.
x^{2}+\frac{100}{25}x=\frac{0}{25}
Dividing by 25 undoes the multiplication by 25.
x^{2}+4x=\frac{0}{25}
Divide 100 by 25.
x^{2}+4x=0
Divide 0 by 25.
x^{2}+4x+2^{2}=2^{2}
Divide 4, the coefficient of the x term, by 2 to get 2. Then add the square of 2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+4x+4=4
Square 2.
\left(x+2\right)^{2}=4
Factor x^{2}+4x+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+2\right)^{2}}=\sqrt{4}
Take the square root of both sides of the equation.
x+2=2 x+2=-2
Simplify.
x=0 x=-4
Subtract 2 from both sides of the equation.