Solve 25m^2-13m-2)-(-16m^2+12m-48)

$$25 m ^ { 2 } - 13 m - 2 ) - ( - 16 m ^ { 2 } + 12 m - 48 )$$

Factor

$$25\left(m-\frac{13-3\sqrt{41}}{50}\right)\left(m-\frac{3\sqrt{41}+13}{50}\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$25m^{2}-13m-2=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$m=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}-4\times 25\left(-2\right)}}{2\times 25}$$

Square -13.

$$m=\frac{-\left(-13\right)±\sqrt{169-4\times 25\left(-2\right)}}{2\times 25}$$

Multiply -4 times 25.

$$m=\frac{-\left(-13\right)±\sqrt{169-100\left(-2\right)}}{2\times 25}$$

Multiply -100 times -2.

$$m=\frac{-\left(-13\right)±\sqrt{169+200}}{2\times 25}$$

Add 169 to 200.

$$m=\frac{-\left(-13\right)±\sqrt{369}}{2\times 25}$$

Take the square root of 369.

$$m=\frac{-\left(-13\right)±3\sqrt{41}}{2\times 25}$$

The opposite of -13 is 13.

$$m=\frac{13±3\sqrt{41}}{2\times 25}$$

Multiply 2 times 25.

$$m=\frac{13±3\sqrt{41}}{50}$$

Now solve the equation m=\frac{13±3\sqrt{41}}{50} when ± is plus. Add 13 to 3\sqrt{41}.

$$m=\frac{3\sqrt{41}+13}{50}$$

Now solve the equation m=\frac{13±3\sqrt{41}}{50} when ± is minus. Subtract 3\sqrt{41} from 13.

$$m=\frac{13-3\sqrt{41}}{50}$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{13+3\sqrt{41}}{50} for x_{1} and \frac{13-3\sqrt{41}}{50} for x_{2}.

$$25m^{2}-13m-2=25\left(m-\frac{3\sqrt{41}+13}{50}\right)\left(m-\frac{13-3\sqrt{41}}{50}\right)$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 25

$$x ^ 2 -\frac{13}{25}x -\frac{2}{25} = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = \frac{13}{25} rs = -\frac{2}{25}$$

Two numbers r and s sum up to \frac{13}{25} exactly when the average of the two numbers is \frac{1}{2}*\frac{13}{25} = \frac{13}{50}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath-gzdabgg4ehffg0hf.b01.azurefd.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = \frac{13}{50} - u s = \frac{13}{50} + u$$

To solve for unknown quantity u, substitute these in the product equation rs = -\frac{2}{25}

$$(\frac{13}{50} - u) (\frac{13}{50} + u) = -\frac{2}{25}$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$\frac{169}{2500} - u^2 = -\frac{2}{25}$$

Simplify the expression by subtracting \frac{169}{2500} on both sides

$$-u^2 = -\frac{2}{25}-\frac{169}{2500} = -\frac{369}{2500}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = \frac{369}{2500} u = \pm\sqrt{\frac{369}{2500}} = \pm \frac{\sqrt{369}}{50}$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =\frac{13}{50} - \frac{\sqrt{369}}{50} = -0.124 s = \frac{13}{50} + \frac{\sqrt{369}}{50} = 0.644$$

Evaluate

$$25m^{2}-13m-2$$