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\left(5b^{2}-9c\right)\left(5b^{2}+9c\right)
Rewrite 25b^{4}-81c^{2} as \left(5b^{2}\right)^{2}-\left(9c\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).