Solve for a
a=\frac{b}{5}-\frac{c}{25}-\frac{1}{5}
Solve for b
b=\frac{25a+c+5}{5}
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25a+c=-5+5b
Add 5b to both sides.
25a=-5+5b-c
Subtract c from both sides.
25a=5b-c-5
The equation is in standard form.
\frac{25a}{25}=\frac{5b-c-5}{25}
Divide both sides by 25.
a=\frac{5b-c-5}{25}
Dividing by 25 undoes the multiplication by 25.
a=\frac{b}{5}-\frac{c}{25}-\frac{1}{5}
Divide -5+5b-c by 25.
-5b+c=-5-25a
Subtract 25a from both sides.
-5b=-5-25a-c
Subtract c from both sides.
-5b=-25a-c-5
The equation is in standard form.
\frac{-5b}{-5}=\frac{-25a-c-5}{-5}
Divide both sides by -5.
b=\frac{-25a-c-5}{-5}
Dividing by -5 undoes the multiplication by -5.
b=\frac{c}{5}+5a+1
Divide -5-25a-c by -5.
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