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\left(5a^{4}-2b^{6}\right)\left(5a^{4}+2b^{6}\right)
Rewrite 25a^{8}-4b^{12} as \left(5a^{4}\right)^{2}-\left(2b^{6}\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).