Solve 25a^2+-488a+2304=0

$$25 a ^ { 2 } + - 488 a + 2304 = 0$$

Solve for a

$$a=8$$

$$a = \frac{288}{25} = 11\frac{13}{25} = 11.52$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$25a^{2}-488a+2304=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 25 for a, -488 for b, and 2304 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{-\left(-488\right)±\sqrt{\left(-488\right)^{2}-4\times 25\times 2304}}{2\times 25}$$

Square -488.

$$a=\frac{-\left(-488\right)±\sqrt{238144-4\times 25\times 2304}}{2\times 25}$$

Multiply -4 times 25.

$$a=\frac{-\left(-488\right)±\sqrt{238144-100\times 2304}}{2\times 25}$$

Multiply -100 times 2304.

$$a=\frac{-\left(-488\right)±\sqrt{238144-230400}}{2\times 25}$$

Add 238144 to -230400.

$$a=\frac{-\left(-488\right)±\sqrt{7744}}{2\times 25}$$

Take the square root of 7744.

$$a=\frac{-\left(-488\right)±88}{2\times 25}$$

The opposite of -488 is 488.

$$a=\frac{488±88}{2\times 25}$$

Multiply 2 times 25.

$$a=\frac{488±88}{50}$$

Now solve the equation a=\frac{488±88}{50} when ± is plus. Add 488 to 88.

$$a=\frac{576}{50}$$

Reduce the fraction \frac{576}{50} to lowest terms by extracting and canceling out 2.

$$a=\frac{288}{25}$$

Now solve the equation a=\frac{488±88}{50} when ± is minus. Subtract 88 from 488.

$$a=\frac{400}{50}$$

Divide 400 by 50.

$$a=8$$

The equation is now solved.

$$a=\frac{288}{25} a=8$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$25a^{2}-488a+2304=0$$

Subtract 2304 from both sides of the equation.

$$25a^{2}-488a+2304-2304=-2304$$

Subtracting 2304 from itself leaves 0.

$$25a^{2}-488a=-2304$$

Divide both sides by 25.

$$\frac{25a^{2}-488a}{25}=-\frac{2304}{25}$$

Dividing by 25 undoes the multiplication by 25.

$$a^{2}-\frac{488}{25}a=-\frac{2304}{25}$$

Divide -\frac{488}{25}, the coefficient of the x term, by 2 to get -\frac{244}{25}. Then add the square of -\frac{244}{25} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$a^{2}-\frac{488}{25}a+\left(-\frac{244}{25}\right)^{2}=-\frac{2304}{25}+\left(-\frac{244}{25}\right)^{2}$$

Square -\frac{244}{25} by squaring both the numerator and the denominator of the fraction.

$$a^{2}-\frac{488}{25}a+\frac{59536}{625}=-\frac{2304}{25}+\frac{59536}{625}$$

Add -\frac{2304}{25} to \frac{59536}{625} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

$$a^{2}-\frac{488}{25}a+\frac{59536}{625}=\frac{1936}{625}$$

Factor a^{2}-\frac{488}{25}a+\frac{59536}{625}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(a-\frac{244}{25}\right)^{2}=\frac{1936}{625}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(a-\frac{244}{25}\right)^{2}}=\sqrt{\frac{1936}{625}}$$

Simplify.

$$a-\frac{244}{25}=\frac{44}{25} a-\frac{244}{25}=-\frac{44}{25}$$

Add \frac{244}{25} to both sides of the equation.

$$a=\frac{288}{25} a=8$$