Solve 25-5(2+3)+2(3*(2)-5)=(-6*(2))+14

$$25 - 5 ( 2 + 3 ) + 2 ( 3 \cdot ( 2 ) - 5 ) = ( - 6 \cdot ( 2 ) ) + 14$$

Verify

Solution Steps

Add 2 and 3 to get 5.

$$25-5\times 5+2\left(3\times 2-5\right)=-6\times 2+14$$

Multiply 5 and 5 to get 25.

$$25-25+2\left(3\times 2-5\right)=-6\times 2+14$$

Subtract 25 from 25 to get 0.

$$0+2\left(3\times 2-5\right)=-6\times 2+14$$

Multiply 3 and 2 to get 6.

$$0+2\left(6-5\right)=-6\times 2+14$$

Subtract 5 from 6 to get 1.

$$0+2\times 1=-6\times 2+14$$

Multiply 2 and 1 to get 2.

$$0+2=-6\times 2+14$$

Add 0 and 2 to get 2.

$$2=-6\times 2+14$$

Multiply -6 and 2 to get -12.

$$2=-12+14$$

Add -12 and 14 to get 2.

$$2=2$$

Compare 2 and 2.

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