Solve 25-35/6-(21/6-13/4)

$$25 - 3 \frac { 5 } { 6 } - ( 2 \frac { 1 } { 6 } - 1 \frac { 3 } { 4 } )$$

Evaluate

$$\frac{83}{4}=20.75$$

Solution Steps

Multiply 3 and 6 to get 18.

$$25-\frac{18+5}{6}-\left(\frac{2\times 6+1}{6}-\frac{1\times 4+3}{4}\right)$$

Add 18 and 5 to get 23.

$$25-\frac{23}{6}-\left(\frac{2\times 6+1}{6}-\frac{1\times 4+3}{4}\right)$$

Convert 25 to fraction \frac{150}{6}.

$$\frac{150}{6}-\frac{23}{6}-\left(\frac{2\times 6+1}{6}-\frac{1\times 4+3}{4}\right)$$

Since \frac{150}{6} and \frac{23}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{150-23}{6}-\left(\frac{2\times 6+1}{6}-\frac{1\times 4+3}{4}\right)$$

Subtract 23 from 150 to get 127.

$$\frac{127}{6}-\left(\frac{2\times 6+1}{6}-\frac{1\times 4+3}{4}\right)$$

Multiply 2 and 6 to get 12.

$$\frac{127}{6}-\left(\frac{12+1}{6}-\frac{1\times 4+3}{4}\right)$$

Add 12 and 1 to get 13.

$$\frac{127}{6}-\left(\frac{13}{6}-\frac{1\times 4+3}{4}\right)$$

Multiply 1 and 4 to get 4.

$$\frac{127}{6}-\left(\frac{13}{6}-\frac{4+3}{4}\right)$$

Add 4 and 3 to get 7.

$$\frac{127}{6}-\left(\frac{13}{6}-\frac{7}{4}\right)$$

Least common multiple of 6 and 4 is 12. Convert \frac{13}{6} and \frac{7}{4} to fractions with denominator 12.

$$\frac{127}{6}-\left(\frac{26}{12}-\frac{21}{12}\right)$$

Since \frac{26}{12} and \frac{21}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{127}{6}-\frac{26-21}{12}$$

Subtract 21 from 26 to get 5.

$$\frac{127}{6}-\frac{5}{12}$$

Least common multiple of 6 and 12 is 12. Convert \frac{127}{6} and \frac{5}{12} to fractions with denominator 12.

$$\frac{254}{12}-\frac{5}{12}$$

Since \frac{254}{12} and \frac{5}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{254-5}{12}$$

Subtract 5 from 254 to get 249.

$$\frac{249}{12}$$

Reduce the fraction \frac{249}{12} to lowest terms by extracting and canceling out 3.

$$\frac{83}{4}$$

Factor

$$\frac{83}{2 ^ {2}} = 20\frac{3}{4} = 20.75$$