Solve 25-2-2+[6+c-4-11]

$$25 - 2 - 2 + [ 6 + c - 4 - 11 ]$$

Evaluate

$$c+12$$

Solution Steps

Subtract 2 from 25 to get 23.

$$23-2+6+c-4-11$$

Subtract 2 from 23 to get 21.

$$21+6+c-4-11$$

Add 21 and 6 to get 27.

$$27+c-4-11$$

Subtract 4 from 27 to get 23.

$$23+c-11$$

Subtract 11 from 23 to get 12.

$$12+c$$

Differentiate w.r.t. c

$$1$$

Steps Using Derivative Rule for Sum

Subtract 2 from 25 to get 23.

$$\frac{\mathrm{d}}{\mathrm{d}c}(23-2+6+c-4-11)$$

Subtract 2 from 23 to get 21.

$$\frac{\mathrm{d}}{\mathrm{d}c}(21+6+c-4-11)$$

Add 21 and 6 to get 27.

$$\frac{\mathrm{d}}{\mathrm{d}c}(27+c-4-11)$$

Subtract 4 from 27 to get 23.

$$\frac{\mathrm{d}}{\mathrm{d}c}(23+c-11)$$

Subtract 11 from 23 to get 12.

$$\frac{\mathrm{d}}{\mathrm{d}c}(12+c)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$c^{1-1}$$

Subtract 1 from 1.

$$c^{0}$$

For any term t except 0, t^{0}=1.

$$1$$