Solve 25-19*3+7div12+1=6

$$25 - 19 \times 3 + 7 \div 12 + 1 = 6$$

Verify

Solution Steps

Multiply 19 and 3 to get 57.

$$25-57+\frac{7}{12}+1=6$$

Subtract 57 from 25 to get -32.

$$-32+\frac{7}{12}+1=6$$

Convert -32 to fraction -\frac{384}{12}.

$$-\frac{384}{12}+\frac{7}{12}+1=6$$

Since -\frac{384}{12} and \frac{7}{12} have the same denominator, add them by adding their numerators.

$$\frac{-384+7}{12}+1=6$$

Add -384 and 7 to get -377.

$$-\frac{377}{12}+1=6$$

Convert 1 to fraction \frac{12}{12}.

$$-\frac{377}{12}+\frac{12}{12}=6$$

Since -\frac{377}{12} and \frac{12}{12} have the same denominator, add them by adding their numerators.

$$\frac{-377+12}{12}=6$$

Add -377 and 12 to get -365.

$$-\frac{365}{12}=6$$

Convert 6 to fraction \frac{72}{12}.

$$-\frac{365}{12}=\frac{72}{12}$$

Compare -\frac{365}{12} and \frac{72}{12}.

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