Solve 25(x+2)^2-36=0

$$25 ( x + 2 ) ^ { 2 } - 36 = 0$$

Solve for x

$$x=-\frac{4}{5}=-0.8$$

$$x = -\frac{16}{5} = -3\frac{1}{5} = -3.2$$

Steps by Finding Square Root

Add 36 to both sides of the equation.

$$25\left(x+2\right)^{2}-36+36=36$$

Subtracting 36 from itself leaves 0.

$$25\left(x+2\right)^{2}=36$$

Divide both sides by 25.

$$\frac{25\left(x+2\right)^{2}}{25}=\frac{36}{25}$$

Dividing by 25 undoes the multiplication by 25.

$$\left(x+2\right)^{2}=\frac{36}{25}$$

Take the square root of both sides of the equation.

$$x+2=\frac{6}{5} x+2=-\frac{6}{5}$$

Subtract 2 from both sides of the equation.

$$x+2-2=\frac{6}{5}-2 x+2-2=-\frac{6}{5}-2$$

Subtracting 2 from itself leaves 0.

$$x=\frac{6}{5}-2 x=-\frac{6}{5}-2$$

Subtract 2 from \frac{6}{5}.

$$x=-\frac{4}{5}$$

Subtract 2 from -\frac{6}{5}.

$$x=-\frac{16}{5}$$

The equation is now solved.

$$x=-\frac{4}{5} x=-\frac{16}{5}$$