Solve 25(3x+2)^2-36=0

$$25 ( 3 x + 2 ) ^ { 2 } - 36 = 0$$

Solve for x

$$x=-\frac{4}{15}\approx -0.266666667$$

$$x = -\frac{16}{15} = -1\frac{1}{15} \approx -1.066666667$$

Steps by Finding Square Root

Add 36 to both sides of the equation.

$$25\left(3x+2\right)^{2}-36+36=36$$

Subtracting 36 from itself leaves 0.

$$25\left(3x+2\right)^{2}=36$$

Divide both sides by 25.

$$\frac{25\left(3x+2\right)^{2}}{25}=\frac{36}{25}$$

Dividing by 25 undoes the multiplication by 25.

$$\left(3x+2\right)^{2}=\frac{36}{25}$$

Take the square root of both sides of the equation.

$$3x+2=\frac{6}{5} 3x+2=-\frac{6}{5}$$

Subtract 2 from both sides of the equation.

$$3x+2-2=\frac{6}{5}-2 3x+2-2=-\frac{6}{5}-2$$

Subtracting 2 from itself leaves 0.

$$3x=\frac{6}{5}-2 3x=-\frac{6}{5}-2$$

Subtract 2 from \frac{6}{5}.

$$3x=-\frac{4}{5}$$

Subtract 2 from -\frac{6}{5}.

$$3x=-\frac{16}{5}$$

Divide both sides by 3.

$$\frac{3x}{3}=-\frac{\frac{4}{5}}{3} \frac{3x}{3}=-\frac{\frac{16}{5}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=-\frac{\frac{4}{5}}{3} x=-\frac{\frac{16}{5}}{3}$$

Divide -\frac{4}{5} by 3.

$$x=-\frac{4}{15}$$

Divide -\frac{16}{5} by 3.

$$x=-\frac{16}{15}$$

The equation is now solved.

$$x=-\frac{4}{15} x=-\frac{16}{15}$$